package from011to020;

/**
 * problem 20 - factorial digit sum
 * 
 * n! means n × (n − 1) × ... × 3 × 2 × 1
 * For example, 10! = 10 × 9 × ... × 3 × 2 × 1 = 3628800,
 * and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.
 * Find the sum of the digits in the number 100!
 */

public class Problem020 
{
	public static void main(String[] args)
	{
		
	}
}
